Ho fumana pherimitha ea rhombus: foromo le mesebetsi

Khatisong ena, re tla tšohla mokhoa oa ho bala perimeter ea rhombus le ho sekaseka mehlala ea ho rarolla mathata.

Foromo ea potoloho

1. Ka bolelele ba lehlakore

Pherimitha (P) ea rhombus e lekana le kakaretso ea bolelele ba mahlakore ohle a eona.

P = a + a + a + a

Hobane mahlakore ohle a setšoantšo se fanoeng a lekana, foromo e ka emeloa ka tsela e latelang (lehlakore le atolositsoeng ke 4):

P = 4*a

2. Ka bolelele ba diagonals

Li-diagonal tsa rhombus leha e le efe li kopana ka lehlakoreng la 90 ° 'me li arotsoe ka halofo moo ho kopanang teng, ke hore:

• AO=OC=d₁/2
• BO=OF=d₂/2

Li-diagonal li arola rhombus ka likhutlo tse 4 tse lekanang tse nepahetseng: AOB, AOD, BOC le DOC. Ha re hlahlobeng AOB ka botebo.

U ka fumana lehlakore AB, e leng hypotenuse ea khutlonnetsepa le lehlakore la rhombus, u sebelisa theorem ea Pythagorean:

AB² = AO² + OB²

Re kenya mokhoa ona bolelele ba maoto, a hlalositsoeng ho latela halofo ea diagonal, 'me re fumana:

AB² = (d₁(2)² + (d₂(2)², kapa

Kahoo perimeter ke:

Mehlala ea mesebetsi

Mosebetsi 1

Fumana pherimitha ea rhombus haeba bolelele ba eona bo le 7 cm.

Qeto:

Re sebelisa foromo ea pele, re kenya boleng bo tsejoang ho eona: P u4d 7 * 27 cm uXNUMXd XNUMX cm.

Mosebetsi 2

Sekhahla sa rhombus ke 44 cm. Fumana lehlakore la setšoantšo.

Qeto:

Joalokaha re tseba, P = 4 * a. Ka hona, ho fumana lehlakore le le leng (a), o hloka ho arola potoloho ka tse 'nè: a = P / 4 = 44 cm / 4 = 11 cm.

Mosebetsi 3

Fumana pherimitha ea rhombus haeba li-diagonals tsa eona li tsejoa: 6 le 8 cm.

Qeto:

Re sebelisa mokhoa oo bolelele ba li-diagonal bo amehang ho oona, re fumana: